(X+3)(2x+4)=2x^2+10x+12

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Solution for (X+3)(2x+4)=2x^2+10x+12 equation: 



(X+3)(2X+4)=2X^2+10X+12

We move all terms to the left:

(X+3)(2X+4)-(2X^2+10X+12)=0

We get rid of parentheses

-2X^2+(X+3)(2X+4)-10X-12=0

We multiply parentheses ..

-2X^2+(+2X^2+4X+6X+12)-10X-12=0

We get rid of parentheses

-2X^2+2X^2+4X+6X-10X+12-12=0

We add all the numbers together, and all the variables

=0

X=0/1

X=0

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